Wednesday, May 6, 2020
The Effect Of The Amount Of Naoh On The Gas Volume At 2...
1). Title The Effect of the Amount of NaOH on the Gas Volume at 2 Minutes 2). IV, DV, 3 SVs IV: The amount of base (NaOH) DV: The the volume of gas in mL after 2 minutes. SV: The amount of Hydrogen Peroxide, the amount of reaction time (2 minutes), and the amount of enzyme (catalase). 3). Hypothesis If different amounts of a base (2 mL, 4 mL, 6 mL) were added, then the reaction would produce the most gas at 6 mL because bases have more OH and the extra oxygen will make the reaction take less time because of the enzyme in the raw liver. 4). Materials Safety Goggles, 50 mL granulated cylinder, 10 mL granulated cylinder, glass vial with stopper and pipet, thermometer, plastic shoe box (tub), catalase from chicken liver, pH paper 0.1M NaOH, 3% Hydrogen Peroxide, tweezers, filter paper disks. 5). Procedure Fill bin with water Fill granulated cylinder with water by submerging and make sure no bubbles at the top. Place filter paper disks dipped in catalase on one side of glass vial. Fill the glass vial with 10 mL of 3% hydrogen peroxide and NaOH (2mL, 4mL, or 6mL, depending) on the other side of the glass vial. Quickly cap the tube with the rubber stopper and submerge and make sure dropper is under the granulated cylinder and that the bubbles are going up the cylinder. Record volume of gas (mL) after 2 minutes. 6). Data Table Enzyme Experiment Trials IVs 1 2 3 Averages Control 40 mL 80 mL 70 mL 63.3 mL Base 2 mL 70 mL 55 mL 63 mL 62.67 mL Base 4 mL 50 mLShow MoreRelatedChemical Reaction and Solution2470 Words à |à 10 Pagessolubility of Cu(OH)2(s) is 1.72 x10ââ¬â6 g/100. mL of solution at 25à ° C. (i) Write the balanced chemical equation for the dissociation of Cu(OH)2(s) in aqueous solution. Cu(OH)2 Cu 2+ + 2 OH ââ¬â (ii) Calculate the solubility (in mol/L) of Cu(OH)2 at 25 à °C. (1.72 x10ââ¬â6 g/0.100 L)(1 mol/97.5 g) = 1.76 x10ââ¬â7 mol/L (iii) Calculate the value of the solubility-product constant, Ksp, for Cu(OH)2 at 25 à °C. Ksp = [Cu 2+][OH ââ¬â]2 = [1.76 x10ââ¬â7][3.53 x10ââ¬â7]2 = 2.20 x10ââ¬â20Read MoreMeasuring Reaction Rate Using Volume of Gas Produced1629 Words à |à 7 PagesChemistry 12 Formal Report Measuring Reaction Rate using Volume of Gas Produced By John Doe 23th October 2012 Introduction An essential element of chemistry is finding reaction rates. This is because chemists need to know how long a reaction should take. In addition to needing to know the rate of a reaction at any point in time to monitor how the reaction is proceeding. Many factors effect reaction rates, two shown above include temperature and concentration. Concentration affects theRead MorePurpose Of The Lab A Chemistry Lab1890 Words à |à 8 Pagesprovided in the lab. 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From there, the fractions of Aspirin releasedRead MoreCorrosion Is A Major Consideration For The Construction Industry5510 Words à |à 23 Pages Department of Civil and Environmental Engineering University College London University of London September 2015 Abstract Sustainablitiy is a major consideration for the construction industryâ⬠¦ ç⺠®Ã¥ ½â¢ Abstract 2 1.Introduction 4 1.1 Introduction 4 1.2 Objectives 5 2. Literature Review 7 2.1 Slag 7 2.2 Slag Activation 7 2.3 AAS Engineering Properties 8 2.4 Passive Film 9 2.5 Corrosion Mechanisms 9 2.6 Test Methods 12 3. Test Materials and Techniques 14 3.1 Test Materials 14 3.2 PastesRead MoreThe Effect Of Oil Recovery On The Economy2237 Words à |à 9 Pagesnatural energy sources are; solution-gas drive, gas-cap drive, natural water drive, fluid and rock expansion, and gravity drainage. The recovery factor after this depletion is usually quite low, and normally only 5-30 % of the original oil in place (OOIP) can be produced. (Reference) 2.1.2 Secondary Recovery Secondary recovery is normally applied when the reservoir natural pressures are not enough to produce hydrocarbons. This process involves injection of water or gas, either for pressure support orRead MoreSodium Chloride and Solution2928 Words à |à 12 PagesWrite your name here Surname Other names Edexcel Certificate Edexcel International GCSE Centre Number Candidate Number Chemistry Unit: KCH0/4CH0 Science (Double Award) KSC0/4SC0 Paper: 1C Monday 21 May 2012 ââ¬â Morning Time: 2 hours You must have: Calculator Paper Reference KCH0/1C 4CH0/1C KSC0/1C 4SC0/1C Total Marks Instructions Use black ink or ball-point pen. Fill in the boxes at the top of this page with your name, centre number and candidate number. Answer all questions
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